1
TG EAPCET 2024 (Online) 9th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If the function

$$ f(x)=\left\{\begin{array}{cc} \frac{\cos a x-\cos 9 x}{x^2} & \text {, if } x \neq 0 \\ 16 & \text {, if } x=0 \end{array}\right. $$

is continuous at $x=0$, then $a=$

A
$\pm 8$
B
$\pm 7$
C
$\pm 6$
D
$\pm 5$
2
TG EAPCET 2024 (Online) 9th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $ f(x)=\left\{\begin{array}{ll}\frac{8}{x^{3}}-6 x & \text {, if } 0 < x \leq 1 \\\\ \frac{x-1}{\sqrt{x}-1} & \text {,if } x > 1\end{array}\right. $ is a real valued function, then at $ x=1, f $ is

A
continuous and differentiable
B
continuous but not differentiable
C
neither continuous nor differentiable
D
differentiable but not continuous
3
TG EAPCET 2024 (Online) 9th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
If $2 x^2-3 x y+4 y^2+2 x-3 y+4=0$, then $\left(\frac{d y}{d x}\right)_{(3,2)}=$
A
-5
B
$\frac{5}{7}$
C
-2
D
$\frac{2}{7}$
4
TG EAPCET 2024 (Online) 9th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $x=\frac{9 t^2}{1+t^4}$ and $y=\frac{16 t^2}{1-t^4}$ then $\frac{d y}{d x}=$

A
$\frac{16}{9}\left(\frac{1-t^4}{1+t^4}\right)^3$
B
$\frac{16}{9} \frac{\left(1-t^4\right)}{\left(1+t^4\right)}$
C
$\frac{9}{16} \frac{\left(1-t^4\right)}{\left(1+t^4\right)}$
D
$\frac{16}{9}\left(\frac{1+t^4}{1-t^4}\right)^3$
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