1
TS EAMCET 2023 (Online) 13th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Velocities $(v)$ and accelerations (a) in two systems of units 1 and 2 are related as $v_2=\frac{n}{m^2} v_1$ and $a_2=\frac{a_1}{m n}$ respectively. Here $m$ and $n$ are constants. Dimensionally relations between distances ( $s_1$ and $s_2$ ) and times ( $t_1$ and $t_2$ ) in the two systems are respectively

A

$s_2=\left(\frac{n}{m}\right)^3 s_1$ and $t_2=\frac{n^2}{m} t_1$

B

$s_2=\left(\frac{n}{m}\right)^3 s_1$ and $t_2=\frac{m}{n^2} t_1$

C

$s_2=\frac{m}{n^2} s_1$ and $t_2=\frac{m^2}{n^4} t_1$

D

$s_2=\frac{n^2}{m} s_1$ and $t_2=\frac{m^2}{n^4} t_1$

2
TS EAMCET 2023 (Online) 13th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A body starts rest with uniform acceleration. If its velocity after $n^{\text {th }}$ second (last second) is $v$ then its displacement in the last two seconds is

A

$\frac{2 v(n+1)}{n}$

B

$\frac{v(n+1)}{n}$

C

$\frac{v(n-1)}{n}$

D

$\frac{2 v(n-1)}{n}$

3
TS EAMCET 2023 (Online) 13th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A stone projected from the ground with a velocity $50 \mathrm{~ms}^{-1}$ at an angle of $30^{\circ}$ with the horizontal crosses a wall after a time of 3 s . Then the horizontal distance beyond the wall that the stone strikes the ground is (acceleration due to gravity $=10 \mathrm{~ms}^{-2}$ )

A

90.2 m

B

89.6 m

C

86.6 m

D

70.2 m

4
TS EAMCET 2023 (Online) 13th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A body of weight 50 N is placed on a horizontal surface as shown in the figure. The minimum force required to move the body is 28.28 N . The frictional force and the normal reaction are respectively

TS EAMCET 2023 (Online) 13th May Morning Shift Physics - Laws of Motion Question 19 English
A

$10 \mathrm{~N}, 15 \mathrm{~N}$

B

$20 \mathrm{~N}, 30 \mathrm{~N}$

C

$2 \mathrm{~N}, 3 \mathrm{~N}$

D

$5 \mathrm{~N}, 6 \mathrm{~N}$

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