1
TS EAMCET 2020 (Online) 11th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

A person moves 30 m North and then 20 m towards East and finally $30 \sqrt{2} \mathrm{~m}$ in South-West direction. The displacement of the person from the origin will be

A

10 m along North

B

10 m along South

C

10 m along West

D

zero

2
TS EAMCET 2020 (Online) 11th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

A particle moving along $X$-axis has acceleration $f$ at time $t$ given by $f=f_0\left(1-\frac{t}{T}\right)$, where $f_0$ and $T$ are constants. The particle at $t=0$ has zero velocity. In the time interval between $t=0$ and the instant when $f=0$, the particle's velocity is

A

$\frac{1}{2} f_0 T^2$

B

$f_0 T^2$

C

$\frac{1}{2} f_0 T$

D

$f_0 T$

3
TS EAMCET 2020 (Online) 11th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

Consider the following vectors.

TS EAMCET 2020 (Online) 11th September Morning Shift Physics - Vector Algebra Question 3 English

Choose the correct statement.

A

$\mathbf{E}=\mathbf{A}-\mathbf{B}$ and $\mathbf{A}=\mathbf{D}+\mathbf{C}$

B

$-\mathbf{E}=-\mathbf{A}+\mathbf{B}$ and $\mathbf{A}=-\mathbf{D}+\mathbf{C}$

C

$\mathbf{E}=-\mathbf{A}-\mathbf{B}$ and $\mathbf{E}=-\mathbf{B}+\mathbf{D}+\mathbf{C}$

D

$\mathbf{E}=-\mathbf{A}-\mathbf{B}$ and $\mathbf{E}=-\mathbf{B}+\mathbf{C}-\mathbf{D}$

4
TS EAMCET 2020 (Online) 11th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

A river 200 m wide is flowing at a rate of $3.0 \mathrm{~m} / \mathrm{s}$. A boat is sailing at a velocity of $15 \mathrm{~m} / \mathrm{s}$ with respect to the water in a direction perpendicular to the river. How far from the point directly opposite to the starting point does the boat reach on the opposite bank?

A

25 m

B

60 m

C

40 m

D

50 m

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