Let $[A]_{3 \times 3}$ be a non-singular matrix such that

$$ A^{-1}=\frac{1}{3}\left(A^2-5 A+7 I\right) . $$

Then $17 A^8-85 A^7+119 A^6-51 A^5-19 A^4+95 A^3-133 A^2+58 A+I=$

If $\left[\begin{array}{ccc}2 & 1 & 1 \\ 0 & 3 & -1 \\ 1 & -1 & 1\end{array}\right]\left[\begin{array}{l}x \\ y \\ z\end{array}\right]=\left[\begin{array}{l}1 \\ 1 \\ 0\end{array}\right]$, then $\left[\begin{array}{l}x \\ y \\ z\end{array}\right]=$

For some $a, b, c \in \mathbf{R}$, if $\sin 5 \theta=a \cos ^4 \theta \sin \theta+b \cos ^2 \theta \sin ^3 \theta+c \sin ^5 \theta$, then $a b c=$

$A\left(z_1=2+2 i\right), B\left(z_2\right), C\left(z_3\right)$ are three points on the Argand plane satisfying $\left|z_k-2 i\right|=2,(k=1,2,3)$. If $\triangle A B C$ encloses the maximum area, then the sum of the imaginary parts of $z_2$ and $z_3$ is