Identify the correct orders regarding atomic radii

(i) $\mathrm{Cl}>\mathrm{F}>\mathrm{Li}$

(ii) $\mathrm{P}>\mathrm{C}>\mathrm{N}$

(iii) $\mathrm{Tm}>\mathrm{Sm}>\mathrm{Eu}$

(iv) $\mathrm{Sr}>\mathrm{Ca}>\mathrm{Mg}$

$$ \text { Match the following } $$

$$ \begin{array}{cccc} \hline & \text { List-I (Elements) } & & \text { List-II (Group) } \\ \hline \text { A } & \mathrm{Mn}, \mathrm{Tc}, \mathrm{Re} & \text { I } & 12 \\ \hline \text { B } & \mathrm{Zn}, \mathrm{Cd}, \mathrm{Hg} & \text { II } & 4 \\ \hline \text { C } & \mathrm{Ti}, \mathrm{Zr}, \mathrm{Hf} & \text { III } & 17 \\ \hline \text { D } & \mathrm{Ga}, \mathrm{In}, \mathrm{Tl} & \text { IV } & 7 \\ \hline & & \text { V } & 13 \\ \hline \end{array} $$

The correct answer is

The atomic numbers of the elements $X, Y, Z$ are $a, a+1, a+2$ respectively. $Z$ is an alkali metal. The nature of bonding in the compound formed by $X$ and $Z$ is

The sets of molecules in which central atom has no lone pair of electrons are

I. $\mathrm{SnCl}_2, \mathrm{NH}_3, \mathrm{SF}_4$

II. $\mathrm{HgCl}_2, \mathrm{SO}_3, \mathrm{SF}_6$

III. $\mathrm{BeCl}_2 \mathrm{BF}_3, \mathrm{PCl}_5$

IV. $\mathrm{ClF}_3, \mathrm{BrF}_5, \mathrm{XeF}_6$