1
TG EAPCET 2025 (Online) 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Consider the following

Assertion

$$ \begin{aligned} & \text { (A) } \begin{array}{r} \sqrt{x-3}\left(\sin ^{-1}(\log x)+\cos ^{-1}\right. \\ (\log x) d x=\frac{\pi}{3}(x-3)^{3 / 2}+c \end{array} \end{aligned} $$

Reason $(\mathrm{R}) \sin ^{-1}(f(x))+\cos ^{-1}(f(x))=\frac{\pi}{2},|f(x)|<1$

The correct answer is

A

Both $(A)$ and $(B)$ are true and $(R)$ is the correct explanation of $(A)$.

B

Both (A) and (R) are true and (R) is not the correct explanation of (A).

C

(A) is true, but (R) is false.

D

(A) is false, but (R) is true.

2
TG EAPCET 2025 (Online) 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

$$ \lim _{n \rightarrow \infty} \frac{\left(2 n(2 n-1) \ldots .(n+2)(n+1)^{1 / n}\right.}{n}= $$

A

$\int_0^1 \log x d x$

B

$\int_0^1 x \log x d x$

C

$\int_0^1(x+1) \log (x+1) d x$

D

$\int_0^1 \log (1+x) d x$

3
TG EAPCET 2025 (Online) 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The area of the region bounded by $y=x^3, X$-axis, $x=-2$ and $x=4$ is

A

64

B

$81 / 4$

C

$66 / 5$

D

68

4
TG EAPCET 2025 (Online) 4th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $\int_0^{\frac{\pi}{2}} \tan ^{14}\left(\frac{x}{2}\right) d x=2\left[\sum_{n=1}^7 f(n)-\frac{\pi}{4}\right]$, then $f(n)=$

A

$\frac{(-1)^n}{n-1}$

B

$\frac{(-1)^n}{2 n+1}$

C

$\frac{(-1)^{n+1}}{2 n-1}$

D

$\frac{(-1)^{n+1}}{n+1}$

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