1
TG EAPCET 2025 (Online) 3rd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

$$ \int x \tan ^{-1} \sqrt{\frac{1+x^2}{1-x^2}} d x= $$

A

$\frac{x^2}{4}\left(\pi-\cos ^{-1} x^2\right)+\frac{1}{4} \sqrt{1-x^2}+C$

B

$\frac{x^2}{4}\left(\pi-\cos ^{-1} x^2\right)+\frac{1}{4} \sqrt{1-x^4}+C$

C

$\frac{x^2}{4}\left(\pi+\cos ^{-1} x^2\right)-\frac{1}{4} \sqrt{1-x^4}+C$

D

$\frac{x^2}{4}\left(\pi+\cos ^{-1} x^2\right)-\frac{1}{4} \sqrt{1-x^2}+C$

2
TG EAPCET 2025 (Online) 3rd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

$$ \int \frac{1}{(2 \cos x+\sin x)^2} d x= $$

A

$\frac{1}{2+\tan x}+C$

B

$-\frac{1}{2 \tan x+1}+C$

C

$\frac{\cos x}{\cos x+2 \sin x}+C$

D

$-\frac{\cos x}{2 \cos x+\sin x}+C$

3
TG EAPCET 2025 (Online) 3rd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

$$ \int_{-1}^1 \frac{\log 2-\log (1+x)}{\sqrt{1-x^2}} d x= $$

A

$\frac{\pi}{8} \log 2$

B

$-\frac{\pi}{2} \log 2$

C

$-\frac{\pi}{4} \log 2$

D

$2 \pi \log 2$

4
TG EAPCET 2025 (Online) 3rd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

$$ \int_0^{\frac{\pi}{4}} \frac{\sec x}{3 \cos x+4 \sin x} d x= $$

A

$\log \left(\frac{7}{3}\right)$

B

$\frac{1}{4} \log \left(\frac{7}{3}\right)$

C

$\frac{1}{4} \log 7$

D

$\log 7$

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