1
TG EAPCET 2025 (Online) 3rd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The probability distribution of a random variable $X$ is given below. Then, the standard deviation of $X$ is

$$ \begin{array}{llllll} \hline \boldsymbol{X}=\boldsymbol{x}_1 & 2 & 3 & 5 & 7 & 12 \\ \hline \boldsymbol{P}\left(\boldsymbol{X}=\boldsymbol{x}_1\right) & 3 k & k & k & 2 k & k \\ \hline \end{array} $$

A

5

B

11

C

$\sqrt{11}$

D

$\sqrt{5}$

2
TG EAPCET 2025 (Online) 3rd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If the mean and variance of a binomial distribution are $\frac{4}{3}$ and $\frac{10}{9}$ respectively, then $P(X \geq 6)=$

A

$\frac{41}{6^8}$

B

$\frac{741}{6^8}$

C

$1-\frac{741}{6^8}$

D

$1-\frac{41}{6^8}$

3
TG EAPCET 2025 (Online) 3rd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A straight line passing through a point $(3,2)$ cuts $X$ and $Y$ axes at the points $A$ and $B$ respectively. If a point $P$ divides $A B$ in the ratio $2: 3$, then the equation of the locus of point $P$ is

A

$\frac{9}{x}+\frac{4}{y}=1$

B

$9 x+4 y=5 x y$

C

$4 x+9 y=5 x y$

D

$\frac{4}{x}+\frac{9}{y}=1$

4
TG EAPCET 2025 (Online) 3rd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

By shifting the origin to the point $(-1,2)$ through translation of axes, if $a x^2+2 h x y+b y^2+2 g x+2 f y+c=0$ is the transformed equation of $2 x^2-x y+y^2-3 x+4 y-5=0$, then $2(f+g+h)=$

A

$a+b+c$

B

$a-5(b+c)$

C

$3(a+b+c)$

D

$c-5(a+b)$

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