1
TG EAPCET 2025 (Online) 3rd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $x=\sqrt{1-\tan y}$, then $\frac{d y}{d x}=$

A

$\frac{2 x}{x^4+2 x^2+2}$

B

$-\frac{2 x}{x^4-2 x^2+2}$

C

$\frac{2 x}{x^4-2 x^2+2}$

D

$-\frac{2 x}{x^4+2 x^2+2}$

2
TG EAPCET 2025 (Online) 3rd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $y=\sec ^{-1} x$, then $\frac{d^2 y}{d x^2}=$

A

$\frac{1-2 x^2}{x|x|\left(x^2-1\right)^{\frac{3}{2}}}$

B

$\frac{1-x^2}{x^2\left(x^2-1\right)^{\frac{3}{2}}}$

C

$\frac{1-x^2}{-x^2\left(x^2-1\right)^{\frac{3}{2}}}$

D

$\frac{1+2 x^2}{x|x|\left(x^2-1\right)^{\frac{3}{2}}}$

3
TG EAPCET 2025 (Online) 3rd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $x=\sin 2 \theta \cos 3 \theta, y=\sin 3 \theta \cos 2 \theta$, then $\frac{d y}{d x}=$

A

$\frac{2 \cos 5 \theta+\sin 3 \theta \sin 2 \theta}{2 \cos 5 \theta-\cos 3 \theta \cos 2 \theta}$

B

$\frac{2 \cos 5 \theta-\sin 3 \theta \sin 2 \theta}{2 \cos 5 \theta+\cos 3 \theta \cos 2 \theta}$

C

$\frac{2 \cos 5 \theta+\cos 3 \theta \cos 2 \theta}{2 \cos 5 \theta-\sin 3 \theta \sin 2 \theta}$

D

$\frac{2 \cos 5 \theta-\sin 3 \theta \sin 2 \theta}{2 \cos 5 \theta-\cos 3 \theta \cos 2 \theta}$

4
TG EAPCET 2025 (Online) 3rd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If the tangent and the normal drawn to the curve $x y^2+x^2 y=12$ at the point $(1,3)$ meet the X -axis in $T$ and $N$ respectively, then $T N=$

A

$\frac{7}{5}$

B

$\frac{45}{7}$

C

$\frac{3 \sqrt{274}}{7}$

D

$\frac{274}{35}$

TS EAMCET Papers

All year-wise previous year question papers