1
MHT CET 2026 19th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
Light travels a distance 'x' in time '$t_0$' in air and '$4x$' in time '$t_1$' in another denser medium. The critical angle for this medium is
A
$\sin^{-1}\left(\dfrac{t_1}{t_0}\right)$
B
$\sin^{-1}\left(\dfrac{4t_0}{t_1}\right)$
C
$\sin^{-1}\left(\dfrac{4t_1}{t_0}\right)$
D
$\sin^{-1}\left(\dfrac{t_0}{4t_1}\right)$
2
MHT CET 2026 19th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
In a biprism experiment, a steady interference pattern is observed on the screen kept at a distance of 100 cm using a light of wavelength $5000$ Å. Without changing the distance between the virtual images of the slit, the source of light is replaced by a source of wavelength $6400$ Å. Now, to reduce the fringe width by $20\%$ of its initial value, the screen should be moved
A
towards the source by $37.5$ cm
B
towards the source by $62.5$ cm
C
away from the source by $62.5$ cm
D
away from the source by $37.5$ cm
3
MHT CET 2026 19th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
A ray of light is incident at polarising angle $\theta$ on air-glass interface. If $\lambda_a$ and $\lambda_g$ are the wavelengths of light in air and glass respectively then
A
$\lambda_a = \lambda_g \cot\theta$
B
$\lambda_g = \lambda_a \cot\theta$
C
$\lambda_a = \lambda_g \tan^2\theta$
D
$\lambda_g = \lambda_a \tan^2\theta$
4
MHT CET 2026 19th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
In biprism experiment, the maximum intensity is $I_0$. If the path difference between the two interfering waves is $\dfrac{\lambda}{3}$, then intensity at the point on the screen is
[$\sin 30^\circ = \cos 60^\circ = 0.5$, $\sin 60^\circ = \cos 30^\circ = \sqrt{3}/2$]
A
$\dfrac{I_0}{4}$
B
$\dfrac{I_0}{3}$
C
$\dfrac{I_0}{2}$
D
$I_0$

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