1
MHT CET 2026 19th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
A particle executing linear S.H.M. has velocities $V_1$ and $V_2$ at distance $x_1$ and $x_2$ respectively, from the mean position, its angular velocity is
A
$\sqrt{\dfrac{V_2^2 - V_1^2}{x_1^2 - x_2^2}}$
B
$\sqrt{\dfrac{V_2^2 - V_1^2}{x_2^2 - x_1^2}}$
C
$\sqrt{\dfrac{V_2^2 - V_1^2}{x_1 x_2}}$
D
$\sqrt{\dfrac{V_1 V_2}{x_1 + x_2}}$
2
MHT CET 2026 19th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
In a resonance tube open at one end, the end correction is $1.1$ cm. If the shortest length of resonating air column with a tuning fork is $18$ cm, the next resonating length will be
A
$45.9$ cm
B
$49.6$ cm
C
$51.3$ cm
D
$56.2$ cm
3
MHT CET 2026 19th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
For stationary wave, $y = 12\cos\left(\dfrac{\pi x}{10}\right)\sin(36\pi t)$ cm, the distance between a node and the successive antinode is
A
$20$ cm
B
$12$ cm
C
$10$ cm
D
$5$ cm
4
MHT CET 2026 19th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
Two waves of same frequency ($n$) approaching each other with same velocity of $18$ m/s interfere. The distance between two consecutive antinodes is
A
$\dfrac{18}{n}$
B
$\dfrac{10}{n}$
C
$\dfrac{9}{n}$
D
$\dfrac{n}{18}$

MHT CET Papers

All year-wise previous year question papers