MHT CET 2026 18th April Morning Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2026 18th April Morning Shift

MCQ (Single Correct Answer)

-0

By connecting a resistance of $980\ \Omega$ in series with a galvanometer, it is converted into a voltmeter of a certain range. When the resistance of $470\ \Omega$ is connected in series, the range is halved. The resistance of the galvanometer is

$30\ \Omega$

$40\ \Omega$

$50\ \Omega$

$60\ \Omega$

MHT CET 2026 18th April Morning Shift

MCQ (Single Correct Answer)

-0

The region inside a current carrying toroid is filled with a material (Niobium) having susceptibility $\chi = 2.6 \times 10^{-5}$. The percentage increase in the magnetic field in the presence of Niobium over that without it, is

$2.6 \times 10^{-5}$

$2.6 \times 10^{-4}$

$2.6 \times 10^{-3}$

$2.6 \times 10^{2}$

MHT CET 2026 18th April Morning Shift

MCQ (Single Correct Answer)

-0

In the following figure, the magnitude of the magnetic field at point 'O' will be
MHT CET 2026 18th April Morning Shift Physics - Moving Charges and Magnetism Question 2 English

MHT CET 2026 18th April Morning Shift Physics - Moving Charges and Magnetism Question 2 English

$\dfrac{\mu_0}{4\pi}\dfrac{I}{r}\left(\dfrac{2}{\pi}+2\right)$

$\dfrac{\mu_0}{4\pi}\dfrac{I}{r}\left(\dfrac{2}{\pi}-2\right)$

$\dfrac{\mu_0}{4\pi}\dfrac{I}{r}\left(2+\dfrac{\pi}{2}\right)$

$\dfrac{\mu_0}{4\pi}\dfrac{I}{r}\left(2-\dfrac{\pi}{2}\right)$

MHT CET 2026 18th April Morning Shift

MCQ (Single Correct Answer)

-0

The ratio of magnetic field at the centre of the current carrying circular loop and its magnetic moment is '$x$'. When both the current and radius are tripled, then the ratio will be

$\dfrac{x}{27}$

$\dfrac{x}{9}$

$\dfrac{x}{3}$

$3x$

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