1
MHT CET 2026 18th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
A solid cylinder and a solid sphere having the same mass and radius roll down on the same smooth inclined plane. The ratio of the acceleration of the cylinder $(a_c)$ to that of the sphere $(a_s)$ is
A
$\dfrac{14}{15}$
B
$\dfrac{15}{14}$
C
$\dfrac{13}{14}$
D
$\dfrac{11}{15}$
2
MHT CET 2026 18th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
The radius of gyration K of a hollow sphere of mass M and radius R about an axis XY is equal to R as shown in figure. The distance of that axis from the center of the sphere is h. The value of h is
MHT CET 2026 18th April Morning Shift Physics - Rotational Motion Question 1 English
A
$\dfrac{R}{\sqrt{3}}$
B
$\dfrac{R}{2}$
C
$\dfrac{R}{\sqrt{2}}$
D
$\dfrac{2R}{\sqrt{3}}$
3
MHT CET 2026 18th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
The lengths of seconds pendulums on the surface of the earth and at an altitude '$h$' from the surface of the earth are $l_s$ and $l_h$ respectively. The radius of the earth is
A
$\dfrac{h\sqrt{l_h}}{\sqrt{l_s}-\sqrt{l_h}}$
B
$\dfrac{h\sqrt{l_h}}{\sqrt{l_h}-\sqrt{l_s}}$
C
$\dfrac{\sqrt{l_h}}{h(\sqrt{l_s}-\sqrt{l_h})}$
D
$\dfrac{\sqrt{l_s}}{h(\sqrt{l_h}-\sqrt{l_s})}$
4
MHT CET 2026 18th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
Time period of a simple pendulum is $T_1$ when on the earth's surface and $T_2$ when taken to a height '2R' above the earth's surface, where 'R' is the radius of the earth. The ratio $T_1 : T_2$ is
A
$1 : 2$
B
$1 : 3$
C
$1 : 4$
D
$1 : 5$

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