1
MHT CET 2026 17th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
If $y = [(x+1)(2x+1)(3x+1)\ldots\ldots(nx+1)]^4$, where $n \in N$ and $\dfrac{dy}{dx}$ at $x = 0$ is $2k$, then the value of $k$ is
A
$\dfrac{n(n+1)}{2}$
B
$n(n+1)$
C
$2n(n+1)$
D
$4n(n+1)$
2
MHT CET 2026 17th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
If $f(x) = \cos x \cos 2x \cos 4x \cos 8x \cos 16x$, then $f'\left(\dfrac{\pi}{4}\right)$ is equal to
A
$1$
B
$0$
C
$\sqrt{2}$
D
$\dfrac{1}{\sqrt{2}}$
3
MHT CET 2026 17th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
The derivative of the function $f(x) = \cos^4 x + \sin^4 x,\ 0 \leq x \leq 2\pi$ is positive for
A
$0 < x < \dfrac{\pi}{8}$
B
$\dfrac{\pi}{4} < x < \dfrac{\pi}{2}$
C
$\dfrac{\pi}{2} < x < \dfrac{5\pi}{8}$
D
$\dfrac{5\pi}{8} < x < \dfrac{3\pi}{4}$
4
MHT CET 2026 17th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
The tangent to the curve intersects the Y-axis at point P. A line drawn through point P is perpendicular to this tangent and passes through another point $(1, 0)$. The differential equation of the curve is...
A
$y\dfrac{dy}{dx} - x\left(\dfrac{dy}{dx}\right)^2 = 1$
B
$x\dfrac{dy}{dx} - y\left(\dfrac{dy}{dx}\right)^2 = 1$
C
$y\dfrac{dy}{dx} + x = 1$
D
$x\dfrac{dy}{dx} + y = 1$

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