1
MHT CET 2026 17th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
The value of $3\tan^{-1}\left(\dfrac{1}{2}\right) = \ldots$
A
$\tan^{-1}\left(\dfrac{5}{2}\right)$
B
$\tan^{-1}\left(\dfrac{2}{5}\right)$
C
$\cot^{-1}\left(\dfrac{11}{2}\right)$
D
$\tan^{-1}\left(\dfrac{11}{2}\right)$
2
MHT CET 2026 17th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
If $f(x) = \dfrac{x+2}{x^2-3x+1}$, then the values of $x$ for which $f(x)$ is not defined are
A
$x = \dfrac{3+\sqrt{5}}{2},\ x = \dfrac{3-\sqrt{5}}{2}$
B
$x = \dfrac{-3+\sqrt{5}}{2},\ x = \dfrac{-3-\sqrt{5}}{2}$
C
$x = \dfrac{3+\sqrt{3}}{2},\ x = \dfrac{3-\sqrt{3}}{2}$
D
$x = \dfrac{2+\sqrt{5}}{2},\ x = \dfrac{2-\sqrt{5}}{2}$
3
MHT CET 2026 17th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
If $f : R \to R$ and $g : R \to R$ are defined as $f(x) = 2x - |x|$ and $g(x) = 2x + |x|$, then
A
$(fog)(2) + (gof)(2) = 0$
B
$(fog)(2) - (gof)(-2) = 0$
C
$(fog)(2) - (fog)(-2) = 0$
D
$(gof)(2) + (gof)(-2) = 0$
4
MHT CET 2026 17th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
Which of the following function is discontinuous at $x = 0$ ?
A
$f(x) = (1 + x)^{\frac{2}{x}},$ for $x \neq 0$
$= e^2,$ for $x = 0$
B
$f(x) = \sin x - \cos x,$ for $x \neq 0$
$= -1,$ for $x = 0$
C
$f(x) = \dfrac{e^{\frac{1}{x}} - 1}{e^{\frac{1}{x}} + 1},$ for $x \neq 0$
$= -1,$ for $x = 0$
D
$f(x) = \dfrac{e^{5x} - e^{2x}}{\sin 3x},$ for $x \neq 0$
$= 1,$ for $x = 0$

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