MHT CET 2025 19th April Morning Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2025 19th April Morning Shift

MCQ (Single Correct Answer)

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The angle between the curves $x y=6$ and $x^2 y=12$ is

$\tan ^{-1} \frac{3}{11}$

$\tan ^{-1} \frac{11}{3}$

$\tan ^{-1} \frac{2}{11}$

$\tan ^{-1} \frac{1}{11}$

MHT CET 2025 19th April Morning Shift

MCQ (Single Correct Answer)

-0

In the mean value theorem, $f^{\prime}(c)=\frac{f(b)-f(a)}{b-a}$, if $\mathrm{a}=0, \mathrm{~b}=\frac{1}{2}$ and $\mathrm{f}(x)=x(x-1)(x-2)$, then the value of $c$ is

$1-\frac{\sqrt{15}}{6}$

$\quad 1-\frac{\sqrt{13}}{6}$

$\quad 1-\frac{\sqrt{21}}{6}$

$1+\frac{\sqrt{21}}{6}$

MHT CET 2025 19th April Morning Shift

MCQ (Single Correct Answer)

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$$\int \frac{\sin 2 x}{(a+b \cos x)^2} d x=$$

$\frac{2}{a^2}\left[\log (a+b \cos x)-\frac{a}{a+b \cos x}\right]+c$ where c is the constant of integration.

$\frac{-1}{a^2}\left[\log (a+b \cos x)+\frac{a}{a+b \cos x}\right]+c$, where c is the constant of integration.

$\frac{-2}{b^2}\left[\log (a+b \cos x)+\frac{a}{a+b \cos x}\right]+c$ where c is the constant of integration.

$\frac{-2}{b^2}\left[\log (a+b \cos x)-\frac{a}{a+b \cos x}\right]+c$, where c is the constant of integration.

MHT CET 2025 19th April Morning Shift

MCQ (Single Correct Answer)

-0

If $m_1$ and $m_2$ are the slopes of the lines represented by $a x^2+2 h x y+b y^2=0$ satisfying the condition $16 \mathrm{~h}^2=25 \mathrm{ab}$, then ............ .

$\mathrm{m}_1=\mathrm{m}_2^2$

$m_1=4 m_2$

$\left|m_1-m_2\right|=2$

$\mathrm{m}_1 \mathrm{~m}_2=1$

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