MHT CET 2025 19th April Morning Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2025 19th April Morning Shift

MCQ (Single Correct Answer)

-0

An ellipse has OB as semi-minor axis, S and $\mathrm{S}^{\prime}$ are foci and angle SBS' is a right angle. Then the eccentricity of the ellipse is

$\frac{1}{2}$

$\frac{1}{\sqrt{2}}$

$\sqrt{2}$

$\frac{1}{3}$

MHT CET 2025 19th April Morning Shift

MCQ (Single Correct Answer)

-0

If the directed line makes an angle $45^{\circ}$ and $60^{\circ}$ with the X and Y -axes respectively, then the obtuse angle $\theta$ made by the line with the Z -axis is

$135^{\circ}$

$120^{\circ}$

$160^{\circ}$

$150^{\circ}$

MHT CET 2025 19th April Morning Shift

MCQ (Single Correct Answer)

-0

The derivative of $\tan ^{-1}\left(\sqrt{1+x^2}-1\right)$ is

$\frac{x}{\sqrt{1+x^2}\left(x^2-2 \sqrt{x+1}+1\right)}$

$\frac{x}{\sqrt{1+x^2}\left(x^2-2 \sqrt{1+x^2}+3\right)}$

$\frac{x}{\sqrt{1+x^2}\left(x^2-2 \sqrt{x^2+1}+2\right)}$

$\frac{x}{\sqrt{1+x^2}\left(x^2+2 \sqrt{1+x^2}-3\right)}$

MHT CET 2025 19th April Morning Shift

MCQ (Single Correct Answer)

-0

By dropping a stone in a quiet lake, a wave in the form of circle is generated. The radius of the circular wave increases at the rate of $2.1 \mathrm{~cm} / \mathrm{sec}$. Then the rate of increase of the enclosed circular region, when the radius of the circular wave is 10 cm , is (Given $\pi=\frac{22}{7}$)

$66 \mathrm{~cm}^2 /$ second

$122 \mathrm{~cm}^2 /$ second

$132 \mathrm{~cm}^2 /$ second

$110 \mathrm{~cm}^2 /$ second

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