1
MHT CET 2025 19th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

Let $\overline{\mathrm{OA}}=\overline{\mathrm{a}}, \overline{\mathrm{OB}}=\overline{\mathrm{b}}$ and if the vector along the angle bisector of $\angle \mathrm{AOB}$ is given by $x \frac{\overline{\mathrm{a}}}{|\overline{\mathrm{a}}|}+y \frac{\overline{\mathrm{~b}}}{|\overline{\mathrm{~b}}|}$ then

A
$x-y=0$
B
$x+y=0$
C
$x=2 y$
D
$y=2 x$
2
MHT CET 2025 19th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

In triangle ABC , the point P divides BC internally in the ratio $3: 4$ and Q divides CA internally in the ratio $5: 3$. If AP and BQ intersect in a point $G$, then $G$ divides $A P$ internally in the ratio

A
$2: 1$
B
$5: 7$
C
$7: 5$
D
$1: 2$
3
MHT CET 2025 19th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

The derivative of

$$ y=(1-x)(2-x) \ldots \ldots \ldots \ldots \ldots \ldots(\mathrm{n}-x) $$

at $x=1$ is

A
$(\mathrm{n}-1)$ !
B
$n!$
C
$(-1)(n-1)$ !
D
$(-n)(n-1)$ !
4
MHT CET 2025 19th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $X \sim B(n, p)$ then $\frac{P(X=k)}{P(X=k-1)}=$

A
$\frac{\mathrm{n}-\mathrm{k}}{\mathrm{k}-1} \cdot \frac{\mathrm{p}}{\mathrm{q}}$
B
$\frac{n-k+1}{k+1} \cdot \frac{p}{q}$
C
$\frac{n+1}{k} \cdot \frac{q}{p}$
D
$\frac{n-k+1}{k} \cdot \frac{p}{q}$

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