1
MHT CET 2025 19th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $X \sim B(n, p)$ then $\frac{P(X=k)}{P(X=k-1)}=$

A
$\frac{\mathrm{n}-\mathrm{k}}{\mathrm{k}-1} \cdot \frac{\mathrm{p}}{\mathrm{q}}$
B
$\frac{n-k+1}{k+1} \cdot \frac{p}{q}$
C
$\frac{n+1}{k} \cdot \frac{q}{p}$
D
$\frac{n-k+1}{k} \cdot \frac{p}{q}$
2
MHT CET 2025 19th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

The differential equation of all straight lines passing through the point $(1,-1)$ is

A
$y=(x-1) \frac{\mathrm{d} y}{\mathrm{~d} x}-1$
B
$x=(x-1) \frac{\mathrm{d} y}{\mathrm{~d} x}+1$
C
$y=(x-1) \frac{\mathrm{d} y}{\mathrm{~d} x}$
D
$\quad y=2(x-1) \frac{\mathrm{d} y}{\mathrm{~d} x}$
3
MHT CET 2025 19th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

The first derivative of the function $\left(\cos ^{-1}\left(\sin \sqrt{\frac{1+x}{2}}\right)+x^x\right)$ with respect to $x$ at $x=1$ is

A
$\frac{1}{4}$
B
$\frac{5}{4}$
C
$\frac{-1}{2}$
D
$\frac{3}{4}$
4
MHT CET 2025 19th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

Let $\bar{u}, \bar{v}, \bar{w}$ be the vectors such that $|\overline{\mathrm{u}}|=1,|\overline{\mathrm{v}}|=2,|\overline{\mathrm{w}}|=3$. If the projection $\overline{\mathrm{v}}$ along $\overline{\mathrm{u}}$ is equal to that of $\overline{\mathrm{w}}$ along $\overline{\mathrm{u}}$ and the vectors $\overline{\mathrm{v}}, \overline{\mathrm{w}}$ are perpendicular to each other then $|\overline{\mathrm{u}}-\overline{\mathrm{v}}+\overline{\mathrm{w}}|$ equals

A
$\sqrt{14}$
B
14
C
$\sqrt{7}$
D
2

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