1
MHT CET 2021 21th September Morning Shift
MCQ (Single Correct Answer)
+2
-0

The general solution of the differential equation $$\frac{d y}{d x}=\frac{x+2 y-1}{x+2 y+1}$$ is

A
$$3(x+y)+4 \log |3 x+6 y-1|=K$$
B
$$3(x-y)+4 \log |3 x+6 y-1|=K$$
C
$$6(-x+y)+4 \log |3 x+6 y-1|=K$$
D
$$6(x+y)+4 \log |3 x+6 y-1|=K$$
2
MHT CET 2021 21th September Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $$\mathrm{X}$$ is a random variable with p.m.f. as follows.

$$\begin{aligned} \mathrm{P}(\mathrm{X}=\mathrm{x}) & =\frac{5}{16}, \mathrm{x}=0,1 \\ & =\frac{\mathrm{kx}}{48}, \mathrm{x}=2, \quad \text { then } \mathrm{E}(\mathrm{x})= \\ & =\frac{1}{4}, \mathrm{x}=3 \end{aligned}$$

A
1.1875
B
1.3125
C
1.5625
D
0.5625
3
MHT CET 2021 21th September Morning Shift
MCQ (Single Correct Answer)
+2
-0

A body at an unknown temperature is placed in a room which is held at a constant temperature of $$30^{\circ} \mathrm{F}$$. If after 10 minutes the temperature of the body is $$0^{\circ} \mathrm{F}$$ and after 20 minutes the temperature of the body is $$15^{\circ} \mathrm{F}$$, then the expression for the temperature of the body at any time $$\mathrm{t}$$ is

A
$$\mathrm{T}=-60 \mathrm{e}^{-0.069 \mathrm{t}}-30$$
B
$$\mathrm{T}=-60 \mathrm{e}^{-0.03010 \mathrm{t}}+30$$
C
$$\mathrm{T}=60 \mathrm{e}^{-0.069 t}+30$$
D
$$\mathrm{T}=60 \mathrm{e}^{-0.069 \mathrm{t}}-30$$
4
MHT CET 2021 21th September Morning Shift
MCQ (Single Correct Answer)
+2
-0

The equation of a line passing through $$(\mathrm{p} \cos \propto, \mathrm{p} \sin \propto)$$ ) and making an angle $$(90+\propto)$$ with positive direction of $$\mathrm{X}$$-axis is

A
$$\mathrm{x} \cos \propto-\mathrm{y} \sin \propto=2 \mathrm{p}$$
B
$$\mathrm{x} \sin \propto+\mathrm{y} \cos \propto=\mathrm{p}$$
C
$$\mathrm{x} \cos \propto+\mathrm{y} \sin \propto=\mathrm{p}$$
D
$$\mathrm{x} \cos \propto+\mathrm{y} \sin \propto=3 \mathrm{p}$$
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