1
MHT CET 2021 21th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

An alternating voltge is represented by $$\mathrm{V}=80 \sin (100 \pi \mathrm{t}) \cos (100 \pi \mathrm{t})$$ volt. The peak voltage is

A
$$20 \mathrm{~V}$$
B
$$40 \mathrm{~V}$$
C
$$30 \mathrm{~V}$$
D
$$50 \mathrm{~V}$$
2
MHT CET 2021 21th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

When the value of acceleration due to gravity '$$g$$' becomes $$\frac{g}{3}$$ above surface of height '$$h$$' then relation between '$$h$$' and '$$R$$' is ( $$\mathrm{R}=$$ radius of earth)

A
$$\mathrm{h}=\frac{\mathrm{R}}{\sqrt{3}-1}$$
B
$$\mathrm{h}=\frac{\sqrt{3}}{\mathrm{R}}$$
C
$$h=(\sqrt{2}-1) R$$
D
$$\mathrm{h}=(\sqrt{3}-1) \mathrm{R}$$
3
MHT CET 2021 21th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

In biprism experiment, 21 fringes are observed in a given region using light of wavelength 4800 $$\mathop A\limits^o $$. If light of wavelength 5600 $$\mathop A\limits^o $$ is used, the number of fringes in the same region will be

A
18
B
24
C
14
D
21
4
MHT CET 2021 21th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

A wire of length '$$L$$'; having resistance '$$R$$' falls from a height '$$\ell$$' in earth's horizontal magnetic field '$$B$$'. The current through the wire is ( $$\mathrm{g}=$$ acceleration due to gravity)

A
$$\frac{\mathrm{BL} \sqrt{2 \mathrm{~g} \ell}}{\mathrm{R}}$$
B
$$\frac{\mathrm{BL} \sqrt{2 \mathrm{~g} \ell}}{\mathrm{R}^2}$$
C
$$\frac{2 \mathrm{BLg} \ell}{\mathrm{R}^2}$$
D
$$\frac{\mathrm{B}^2 \mathrm{~L}^2}{\mathrm{R}}$$
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