A line L passes through the point of intersection of the lines $3 x+y-10=0$ and $x-y-2=0$.
If the perpendicular distance of the line $L$ from the point $(5,1)$ is exactly $\frac{2}{\sqrt{5}}$ units, which of the following represents the correct equation for line L ?
$x+2 y-5=0$
$2 x+y-7=0$
$x-2 y+1=0$
$2 x-y-5=0$
$$ \text { The particular solution of the differential equation }(x-y)(d x+d y)=(d x-d y) \text { when } y=-1 \text { and } x=0 \text { is } $$
$$ \log |x+y|=x-y+1 $$
$$ \log \left|\frac{x-y}{x+y}\right|=1 $$
$$ \log |x-y|=x+y+1 $$
$$ \log |x-y|=x-y+1 $$
$$ \int \tan ^{-1}\left(\sqrt{\frac{1-\sin x}{1+\sin x}}\right) d x= $$
$$ \frac{\pi}{4} x-\frac{x^2}{4}+C $$
$$ \frac{\pi}{4} x-\frac{x^2}{2}+C $$
$$ \frac{\pi}{2} x-\frac{x^2}{4}+C $$
$$ \frac{\pi}{4}-\frac{x}{4}+C $$
The area enclosed by the curve $y=-x^2$ and the line $x+y+2=0$ is
$4.5 $ sq units
$3 .5$ sq units
$4 $ sq units
$5 .5$ sq units
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