A parallel combination of ' $n$ ' cells of emf ' $E$ ' and internal resistance ' $r$ ' each, are connected across the external resistance ' $R$ '. If the external resistance ' $R$ ' is negligibly small, then the current ' $I$ ' through the external resistance is:
$I=\frac{E}{n R}$
$I=\frac{E}{R}$
$I=\frac{n E}{R}$
$I=\frac{r E}{n}$
A particle moves along a parabolic path $y=9 x^2$ in such a way that the x component of velocity remains constant. If, the acceleration of the particle is $2 j m s^{-2}$, find the x component of velocity.
$\frac{1}{9} m s^{-1}$
$\frac{1}{4} m s^{-1}$
$\frac{1}{3} m s^{-1}$
$\frac{1}{6} m s^{-1}$
A source of alternating emf $\varepsilon=\varepsilon_0 \sin (\omega t)$ is connected to a capacitor. Then the instantaneous current in the circuit is: ˋ
$ I=I_0 \sin \left(\omega t-\frac{\pi}{2}\right)$
$I=\sqrt{2} I_0 \sin \left(\omega t+\frac{\pi}{2}\right)$
$I=I_0 \sin \omega t$
$I=I_0 \sin \left(\omega t+\frac{\pi}{2}\right)$
If the intensity of the central maximum in the Young's double slit experiment is $\mathrm{I}_0$, what will be the intensity at the same region when one of the slits is blocked by an opaque object?
$\frac{I_0}{2}$
$I_0$
$\frac{I_0}{4}$
$\frac{I_0}{8}$
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