1
COMEDK 2026 Afternoon Shift
MCQ (Single Correct Answer)
+1
-0

Choose the incorrect statement.

A

Propan-2-amine can be obtained by reacting acetoxime with $\mathrm{Na} / \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}$

B

Aniline cannot be prepared by Phthalimide reaction

C

The decreasing order of basic strength of amines in aqueous solution is Ethanamine > $\mathrm{N}, \mathrm{N}$-Dimethylaniline > Benzenamine

D

Fluorobenzene cannot be prepared from Benzenediazonium chloride by Sandmeyer's reaction because Fluorination of the Diazonium salt is highly endothermic in nature

2
COMEDK 2026 Afternoon Shift
MCQ (Single Correct Answer)
+1
-0

The quantity of Ca that can be produced from molten $\mathrm{CaCl}_2$, with the same quantity of electricity (in coulombs) required to produce 4.8 g of Mg from molten $\mathrm{MgCl}_2$ is: [Atomic mass of $\mathrm{Mg}=24 \mathrm{u}$; Atomic mass of $\mathrm{Ca}=40 \mathrm{u}$ ]

A

5.2 g

B

6.0 g

C

8.0 g

D

4.8 g

3
COMEDK 2026 Afternoon Shift
MCQ (Single Correct Answer)
+1
-0

Choose the correct reason:

o-hydroxybenzaldehyde is a liquid at room temperature while $p$-hydroxy-benzaldehyde is a high melting solid, because

A

o-hydroxybenzaldehyde shows only weak Vanderwal's forces of attraction while in $p$ hydroxy benzaldehyde there is strong Vanderwal's forces of attraction in solid state

B

o-hydroxybenzaldehyde shows association of the molecules while in $p$-hydroxy benzaldehyde there is no association among the molecules

C

o-hydroxybenzaldehyde shows intramolecular hydrogen bonding while in $p$-hydroxy benzaldehyde there is no intramolecular hydrogen bonding

D

p-hydroxybenzaldehyde, shows intramolecular hydrogen bonding while in o-hydroxy benzaldehyde there is stronger intermolecular hydrogen bonding

4
COMEDK 2026 Afternoon Shift
MCQ (Single Correct Answer)
+1
-0

The number of bond pairs and lone pairs of electrons in the molecule $I F_5$ is:

A

5,1

B

6,0

C

4,2

D

4,1