$$ \text { The expression } \frac{\tan \left(x-\frac{\pi}{2}\right) \cos \left(\frac{3 \pi}{2}+x\right)-\sin ^3\left(\frac{7 \pi}{2}-x\right)}{\cos \left(x-\frac{\pi}{2}\right) \tan \left(\frac{3 \pi}{2}+x\right)} \text { simplifies to: } $$
$\sin ^2 x$
$\cos ^2 x-\sin ^2 x$
$1+\cos ^2 x$
$-\left(1+\cos ^2 x\right)$
The function $\boldsymbol{x}+\boldsymbol{y}=\boldsymbol{\operatorname { t a n }}^{-\mathbf{1}} \boldsymbol{y}$ is the solution of which of the following differential equations?
$y^2 y^{\prime}-y^2+1=0$
$y^2-2 y^{\prime}+1=0$
$y^2 y^{\prime}+y^2+1=0$
$y^2 y^{\prime \prime}-2 y^{\prime}=0$
The function $f: \mathbb{R} \rightarrow \mathbb{R}$ defined by $f(x)=\frac{x}{x^2+1} \quad \forall x \in \mathbb{R}$ is
One-one and onto
Onto but not one-one
Neither one-one nor onto
One-one but not onto
$$ \begin{aligned} &\text { Consider two skew lines in 3D space. }\\ &M_1: \frac{x-1}{1}=\frac{2-y}{1}=\frac{z-5}{1} \text { and } M_2: \frac{x+3}{1}=\frac{y-7}{2}=\frac{z+4}{1} \end{aligned} $$
Let $L_1$ be the line of shortest distance (common perpendicular) between $M_1$ and $M_2$
If $L_2$ is a line parallel to the vector $\vec{b}=\hat{\jmath}+\hat{k}$,
Then the acute angle $\boldsymbol{\theta}$ between the lines $L_1$ and $L_2$ is:
$30^{\circ}$
$45^{\circ}$
$\cos ^{-1}\left(\frac{1}{3}\right)$
$60^{\circ}$
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