1
COMEDK 2023 Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $$\cos A=m \cos B$$ and $$\cot \left(\frac{A+B}{2}\right)=\lambda \tan \left(\frac{B-A}{2}\right)$$, then $$\lambda$$ is equal to

A
$$\frac{m}{m-1}$$
B
$$\frac{m+1}{m}$$
C
$$\frac{m+1}{m-1}$$
D
None of these
2
COMEDK 2023 Morning Shift
MCQ (Single Correct Answer)
+1
-0

The expression $$\frac{2 \tan A}{1-\cot A}+\frac{2 \cot A}{1-\tan A}$$ can be written as

A
$$\sin 2 A+\cos 2 A$$
B
$$2 \sec A \operatorname{cosec} A+2$$
C
$$\tan 2 A+\cot 2 A$$
D
$$\sec 2 A+\operatorname{cosec} 2 A$$
3
COMEDK 2023 Morning Shift
MCQ (Single Correct Answer)
+1
-0

The general solution of $$2 \cos 4 x+\sin ^2 2 x=0$$ is

A
$$x=\frac{n \pi}{2} \pm \sin ^{-1}\left(\frac{1}{5}\right)$$
B
$$x=\frac{n \pi}{4}+\frac{(-1)^n}{4} \sin ^{-1}\left( \pm \frac{2 \sqrt{2}}{3}\right)$$
C
$$x=\frac{n \pi}{2} \pm \cos ^{-1}\left(\frac{1}{5}\right)$$
D
$$x=\frac{n \pi}{4}+\frac{(-1)^n}{4} \cos ^{-1}\left(\frac{1}{5}\right)$$
4
COMEDK 2023 Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $$2 f\left(x^2\right)+3 f\left(\frac{1}{x^2}\right)=x^2-1, \forall x \in R-\{0\}$$, then $$f\left(x^8\right)$$ is equal to

A
$$\frac{\left(1-x^8\right)\left(2 x^8+3\right)}{5 x^8}$$
B
$$\frac{\left(1+x^8\right)\left(2 x^8-3\right)}{5 x^8}$$
C
$$\frac{\left(1-x^8\right)\left(2 x^8-3\right)}{5 x^8}$$
D
None of these
EXAM MAP