1
COMEDK 2023 Morning Shift
MCQ (Single Correct Answer)
+1
-0

A plane electromagnetic wave of frequency $$20 \mathrm{~MHz}$$ travels through a space along $$x$$-direction. If the electric field vector at a certain point in space is $$6 \mathrm{~Vm}^{-1}$$, then what is the magnetic field vector at that point?

A
$$2 \times 10^{-8} \mathrm{~T}$$
B
$$\frac{1}{2} \times 10^{-8} \mathrm{~T}$$
C
$$2 \mathrm{~T}$$
D
$$\frac{1}{2} \mathrm{~T}$$
2
COMEDK 2023 Morning Shift
MCQ (Single Correct Answer)
+1
-0

The sides of a parallelogram are represented by vectors $$\vec{p}=5 \hat{\mathbf{i}}-4 \hat{\mathbf{j}}+3 \hat{\mathbf{k}}$$ and $$\vec{q}=3 \hat{\mathbf{i}}+2 \hat{\mathbf{j}}-\hat{\mathbf{k}}$$. Then, the area of the parallelogram is

A
$$\sqrt{684}$$ sq units
B
$$\sqrt{72}$$ sq units
C
171 sq units
D
72 sq units
3
COMEDK 2023 Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $$\theta_1$$ and $$\theta_2$$ be the apparent angles of dip observed in two vertical planes at right angles to each other, then the true angle of $$\operatorname{dip} \theta$$ is given by

A
$$\cot ^2 \theta=\cot ^2 \theta_1+\cot ^2 \theta_2$$
B
$$\tan ^2 \theta=\tan ^2 \theta_1+\tan ^2 \theta_2$$
C
$$\cot ^2 \theta=\cot ^2 \theta_1-\cot ^2 \theta_2$$
D
$$\tan ^2 \theta=\tan ^2 \theta_1-\tan ^2 \theta_2$$
4
COMEDK 2023 Morning Shift
MCQ (Single Correct Answer)
+1
-0

Let $$K_1$$ be the maximum kinetic energy of photoelectrons emitted by light of wavelength $$\lambda_1$$ and $$K_2$$ corresponding to wavelength $$\lambda_2$$. If $$\lambda_1=2 \lambda_2$$, then

A
$$2 K_1=K_2$$
B
$$K_1=2 K_2$$
C
$$K_1 < K_2 / 2$$
D
$$K_1>2 K_2$$
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