1
VITEEE 2025
MCQ (Single Correct Answer)
+4
-1

Let $f$ be a non-negative function defined on the interval $[0,1]$. If $\int_0^x \sqrt{1-(f(t))^2} d t =\int_0^x f(t) d t, 0 \leq x \leq 1$ and $f(0)=0$, then

A

$f\left(\frac{1}{2}\right)<\frac{1}{2}$ and $f\left(\frac{1}{3}\right)>\frac{1}{3}$

B

$f\left(\frac{1}{2}\right)<\frac{1}{2}$ and $f\left(\frac{1}{3}\right)<\frac{1}{3}$

C

$f\left(\frac{1}{2}\right)>\frac{1}{2}$ and $f\left(\frac{1}{3}\right)>\frac{1}{3}$

D

$f\left(\frac{1}{2}\right)>\frac{1}{2}$ and $f\left(\frac{1}{3}\right)<\frac{1}{3}$

2
VITEEE 2024
MCQ (Single Correct Answer)
+4
-1

$$ \int_0^\pi\left[\cos ^2\left(\frac{3 \pi}{8}-\frac{x}{4}\right)-\cos ^2\left(\frac{11 \pi}{8}+\frac{x}{4}\right)\right] d x$$ equals to

A
$\sqrt2$
B
$\sqrt3$
C
3
D
2
3
VITEEE 2023
MCQ (Single Correct Answer)
+4
-1

The value of $$\int_\lambda^{\lambda+\pi / 2}\left(\cos ^4 x+\sin ^4 x\right) d x$$ is

A
$$\lambda\left(\frac{\pi}{2}\right)^2$$
B
$$\frac{3 \pi}{4}$$
C
$$\frac{3 \pi}{8}$$
D
$$\left(\frac{3 \pi}{8}\right) \lambda^2$$
4
VITEEE 2023
MCQ (Single Correct Answer)
+4
-1

$$\lim _\limits{n \rightarrow \infty}\left(\frac{(n+1)(n+2) \ldots 3 n}{n^{2 n}}\right)^{1 / n}$$ is equal to

A
$$\frac{18}{e^4}$$
B
$$\frac{27}{e^2}$$
C
$$\frac{9}{e^2}$$
D
$$3 \log 3-2$$

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