1
VITEEE 2025
MCQ (Single Correct Answer)
+4
-1

Sum to 10 terms of the series $1+2(1 \cdot 1)+3(1 \cdot 1)^2+4(1 \cdot 1)^3+$ $\_\_\_\_$ is

A

85.12

B

96.75

C

92.5

D

100

2
VITEEE 2025
MCQ (Single Correct Answer)
+4
-1

$S_n=1 \cdot 3+2 \cdot 2^2+3 \cdot 3^3+4 \cdot 2^4+\ldots \ldots \ldots$ upto $n$ terms. If $S_{20}=a \cdot 3^{21}+b \cdot 2^{22}+\frac{391}{288}$, then value of $32 a-9 b$ is

A

21

B

13

C

17

D

29

3
VITEEE 2024
MCQ (Single Correct Answer)
+4
-1

The sum of the series $1 \cdot 2^2+2 \cdot 4^2+3 \cdot 6^2+\ldots$ upto 10 terms is

A
11300
B
12100
C
12300
D
11200
4
VITEEE 2024
MCQ (Single Correct Answer)
+4
-1

Sum of first ' $n$ ' terms of a series $a_1+a_2+\ldots+a_n$ is given by $S_n=\frac{n\left(n^2-1\right)(n+2)}{4}$, then the value of $\lim _\limits{n \rightarrow \infty} \sum_\limits{r=2}^n \frac{1}{a_r}$ is

A
4
B
2
C
$\frac{1}{4}$
D
$\frac{1}{2}$

VITEEE Subjects

Browse all chapters by subject