VITEEE 2022 | Circle Question 2 | Mathematics

If the tangent at point $$P$$ on the circle $$x^2+y^2+6 x+6 y-2=0$$ meets the straight line $$5 x-2 y+6=0$$ at a point $$Q$$ on $$Y$$-axis, the length of $$P Q$$ is

$$2 \sqrt{5}$$

$$3 \sqrt{5}$$

VITEEE 2022

MCQ (Single Correct Answer)

-0

If a circle of constant radius '$$r$$' passes through the origin and meets the coordinate axes at points $$A$$ and $$B$$ respectively, then the locus of the centroid of triangle $$O A B$$, '$$O$$' being the origin, is

$$x^2+y^2=\frac{4}{9} r^2$$

$$x^2+y^2=\frac{9}{4} r^2$$

$$x^2+y^2=\frac{2}{3} r^2$$

$$x^2+y^2=\frac{3}{2} r^2$$

VITEEE 2022

MCQ (Single Correct Answer)

-0

The image of the centre of the circle $$x^2+y^2=a^2$$ with respect to the mirror $$x+y=1$$ is

$$\left(\frac{1}{\sqrt{2}}, \sqrt{2}\right)$$

$$(\sqrt{2}, \sqrt{2})$$

$$(\sqrt{2,2} \sqrt{2})$$

$$(-\sqrt{2}, 2)$$

None of these

VITEEE 2021

MCQ (Single Correct Answer)

-0

The radius of the circle $$(x \cos \theta+y \sin \theta-a)^2+(x \sin \theta-y \cos \theta-b)^2=k^2$$ is

$$a^2+b^2-k^2$$

$$a \sin \theta-b \cos \theta$$

$$a^2+b^2$$

$$k$$

VITEEE Subjects

Aptitude

Coding and Decoding Number Series Syllogism Data Sufficiency Data Interpretation Classification Series Completion Blood Relations Logical Deduction

English

Comprehension Ability Fill in the Blanks Vocabulary