IAT (IISER) 2025 | Rotational Motion Question 1 | Physics

A circular disk of mass $M$ and radius $R$ is rotating clockwise with a uniform angular velocity $\omega$ about an axis passing through the centre, normal to the disk. At time $t=0$, a torque $T$ is applied along the same axis to oppose the rotation of the disk. What is the angular displacement $\theta$ (measured from $t=0$ in the clockwise direction) that the disk attains before it starts rotating counterclockwise?

$$ \theta=\frac{\omega^2 M R^2}{4 T} $$

$$ \theta=\frac{\omega^2 M R^2}{8 T} $$

$$ \theta=-\frac{\omega^2 M R^2}{4 T} $$

$$ \theta=-\frac{\omega^2 M R^2}{8 T} $$

IAT (IISER) 2024

MCQ (Single Correct Answer)

-1

An inextensible cord of negligible mass passes over the rim of a solid disc of mass $M$ and radius $R$. The disc is free to rotate about an axis passing through the centre perpendicular to the plane of the screen, as shown in the figure. Two blocks of masses $M$ and $\widetilde{M} / 2$ are attached to the two free ends of the cord. Assume that there is no slipping of the cord on the disc. The acceleration due to gravity is $g$. What is the value of the angular acceleration of the disc? IAT (IISER) 2024 Physics - Rotational Motion Question 2 English

IAT (IISER) 2024 Physics - Rotational Motion Question 2 English

$g / R$

$g / 2 R$

$g / 3 R$

$g / 4 R$

IAT (IISER) 2020

MCQ (Single Correct Answer)

-1

Consider a solid rod of mass $m$ and uniform density resting against a vertical wall and horizontal floor as shown in the figure. The coefficients of friction of the rod with the wall and with the floor are given to be $\mu_1$ and $\mu_2$ respectively. Gravity is acting downwards with acceleration due to gravity $g$. What should be the value of the inclination angle $\alpha$ so that the rod stays in equilibrium? IAT (IISER) 2020 Physics - Rotational Motion Question 3 English

IAT (IISER) 2020 Physics - Rotational Motion Question 3 English

$\tan ^{-1}\left(\frac{\mu_1}{\mu_2}\right)$

$\tan ^{-1}\left(\frac{1-\mu_2}{2 \mu_1 \mu_2}\right)$

$\tan ^{-1}\left(\frac{1-\mu_1 \mu_2}{2 \mu_2}\right)$

$\tan ^{-1}\left(\frac{\mu_2}{\mu_1}\right)$ $$ N_1=f_2=\mu_2 N_2 $$

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