Tool life equation for two tools under consideration are as follows

$$\eqalign{ & HSS:\,\,\,\,\,\,\,\,\,\,\,\,\,V{T^{0.2}} = 150 \cr & Carbide:\,\,\,\,\,\,V{T^{0.3}} = 250 \cr} $$
Where $$V$$ is the cutting speed in $$m/min$$ and $$T$$ is the tool life in $$min.$$ The breakdown cutting speed above which the carbide tool will be beneficial is

Two different tools $$A$$ and $$B$$ having nose radius of $$0.6mm$$ and $$0.33mm$$ respectively are used to machine $$C-45$$ steel employing feed rate of $$0.2$$ $$mm/rev$$ and $$0.1mm/rev$$ respectively. The tool that gives better finish and the value of ideal surface roughness are

A $$60deg$$ symmetrical $$V$$ tool is used in shaping a work piece with a depth of cut of $$0.1$$$$mm$$ and feed of $$0.1mm/stroke$$. The theoretical peak to valley height, in $$mm,$$ of the surface produced is

The heat generated in metal cutting is dissipated in different proportions into environment, tool, chip and work-piece. The correct order of this proportion in decreasing magnitude is (no cutting fluid is use ($$d$$)