1
AIIMS 2018
MCQ (Single Correct Answer)
+1
-0.33

A long straight wire, carrying current $$I$$ is bent at its mid-point to form an angle of $$45^{\circ}$$. Induction of magnetic field (in tesla) at point $$P$$, distant $$R$$ from point of bending is equal to

AIIMS 2018 Physics - Moving Charges and Magnetism Question 1 English

A
$$\frac{(\sqrt{2}-1) \mu_0 I}{4 \pi R}$$
B
$$\frac{(\sqrt{2}+1) \mu_0 I}{4 \pi R}$$
C
$$\frac{(\sqrt{2}-1) \mu_0 I}{4 \sqrt{2} \pi R}$$
D
$$\frac{(\sqrt{2}+1) \mu_0 I}{4 \sqrt{2} \pi R}$$
2
AIIMS 2018
MCQ (Single Correct Answer)
+1
-0.33

An element $$d l=d x \hat{\mathbf{i}}$$ (where, $$d x=1 \mathrm{~cm}$$ ) is placed at the origin and carries a large current $$i=10 \mathrm{~A}$$. What is the magnetic field on the $$Y$$-axis at a distance of $$0.5 \mathrm{~m}$$ ?

A
$$2 \times 10^{-8} \hat{\mathbf{k}} T$$
B
$$4 \times 10^{-8} \hat{\mathbf{k}} \mathbf{T}$$
C
$$-2 \times 10^{-8} \hat{\mathbf{k}} T$$
D
$$-4 \times 10^{-8} \hat{\mathbf{k}} T$$
3
AIIMS 2018
MCQ (Single Correct Answer)
+1
-0.33

The horizontal component of the earth's magnetic field at any place is $$0.36 \times 10^{-4} \mathrm{~Wb} / \mathrm{m}^2$$. If the angle of dip at that place is $$60^{\circ}$$, then the value of vertical component of the earth's magnetic field will be (in $$\mathrm{Wb} / \mathrm{m}^2$$ )

A
$$0.12 \times 10^{-4}$$
B
$$0.24 \times 10^{-4}$$
C
$$0.40 \times 10^{-4}$$
D
$$0.622 \times 10^{-4}$$
4
AIIMS 2018
MCQ (Single Correct Answer)
+1
-0.33

Consider the following figure, a uniform magnetic field of 0.2 T is directed along the positive X-axis. The magnetic flux through top surface of the figure.

AIIMS 2018 Physics - Moving Charges and Magnetism Question 4 English

A
zero
B
0.8 m-Wb
C
1.0 m-Wb
D
$$-$$1.8 m-Wb
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