1
WB JEE 2022
MCQ (Single Correct Answer)
+1
-0.25
Change Language

The line $$x - 2y + 4z + 4 = 0$$, $$x + y + z - 8 = 0$$ intersect the plane $$x - y + 2z + 1 = 0$$ at the point

A
$$( - 2,5,1)$$
B
$$(2, - 5,1)$$
C
$$(2,5, - 1)$$
D
$$(2,5,1)$$
2
WB JEE 2022
MCQ (Single Correct Answer)
+2
-0.5
Change Language

If I is the greatest of $${I_1} = \int\limits_0^1 {{e^{ - x}}{{\cos }^2}x\,dx} $$, $${I_2} = \int\limits_0^1 {{e^{ - {x^2}}}{{\cos }^2}x\,dx} $$, $${I_3} = \int\limits_0^1 {{e^{ - {x^2}}}dx} $$, $${I_4} = \int\limits_0^1 {{e^{ - {x^2}/2}}dx} $$, then

A
I = I1
B
I = I2
C
I = I3
D
I = I4
3
WB JEE 2022
MCQ (Single Correct Answer)
+2
-0.5
Change Language

$$\mathop {\lim }\limits_{x \to \infty } \left( {{{{x^2} + 1} \over {x + 1}} - ax - b} \right),(a,b \in R)$$ = 0. Then

A
a = 0, b = 1
B
a = 1, b = $$-$$1
C
a = $$-$$1, b = 1
D
a = 0, b = 0
4
WB JEE 2022
MCQ (Single Correct Answer)
+2
-0.5
Change Language

If the transformation $$z = \log \tan {x \over 2}$$ reduces the differential equation

$${{{d^2}y} \over {d{x^2}}} + \cot x{{dy} \over {dx}} + 4y\cos e{c^2}x = 0$$ into the form $${{{d^2}y} \over {d{z^2}}} + ky = 0$$ then k is equal to

A
$$-$$4
B
4
C
2
D
$$-$$2
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