1
WB JEE 2022
MCQ (Single Correct Answer)
+1
-0.25
Change Language

$$\mathop {\lim }\limits_{x \to 0} \left( {{1 \over x}\ln \sqrt {{{1 + x} \over {1 - x}}} } \right)$$ is

A
$${1 \over 2}$$
B
0
C
1
D
does not exist
2
WB JEE 2022
MCQ (Single Correct Answer)
+1
-0.25
Change Language

Let f : [a, b] $$\to$$ R be continuous in [a, b], differentiable in (a, b) and f(a) = 0 = f(b). Then

A
there exists at least one point $$c \in (a,b)$$ for which $$f'(c) = f(c)$$
B
$$f'(x) = f(x)$$ does not hold at any point of (a, b)
C
at every point of $$(a,b),f'(x) > f(x)$$
D
at every point of $$(a,b),f'(x) < f(x)$$
3
WB JEE 2022
MCQ (Single Correct Answer)
+1
-0.25
Change Language

$$I = \int {\cos (\ln x)dx} $$. Then I =

A
$${x \over 2}\{ \cos (\ln x) + \sin (\ln x)\} + c$$ (c denotes constant of integration)
B
$${x^2}\{ \cos (\ln x) - \sin (\ln x)\} + c$$ (c denotes constant of integration)
C
$${x^2}\sin (\ln x) + c$$ (c denotes constant of integration)
D
$$x\cos (\ln x) + c$$ (c denotes constant of integration)
4
WB JEE 2022
MCQ (Single Correct Answer)
+1
-0.25
Change Language

Let f be derivable in [0, 1], then

A
there exists $$c \in (0,1)$$ such that $$\int\limits_0^c {f(x)dx = (1 - c)f(c)} $$
B
there does not exist any point $$d \in (0,1)$$ for which $$\int\limits_0^d {f(x)dx = (1 - d)f(d)} $$
C
$$\int\limits_0^c {f(x)dx} $$ does not exist, for any $$c \in (0,1)$$
D
$$\int\limits_0^c {f(x)dx} $$ is independent of $$c,c \in (0,1)$$
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