1
WB JEE 2022
MCQ (Single Correct Answer)
+1
-0.25
Change Language

Two circles $${S_1} = p{x^2} + p{y^2} + 2g'x + 2f'y + d = 0$$ and $${S_2} = {x^2} + {y^2} + 2gx + 2fy + d' = 0$$ have a common chord PQ. The equation of PQ is

A
$${S_1} - {S_2} = 0$$
B
$${S_1} + {S_2} = 0$$
C
$${S_1} - p{S_2} = 0$$
D
$${S_1} + p{S_2} = 0$$
2
WB JEE 2022
MCQ (Single Correct Answer)
+1
-0.25
Change Language

Let $$P(3\sec \theta ,2\tan \theta )$$ and $$Q(3\sec \phi ,2\tan \phi )$$ be two points on $${{{x^2}} \over 9} - {{{y^2}} \over 4} = 1$$ such that $$\theta + \phi = {\pi \over 2},0 < \theta ,\phi < {\pi \over 2}$$. Then the ordinate of the point of intersection of the normals at P and Q is

A
$${{13} \over 2}$$
B
$$ - {{13} \over 2}$$
C
$${5 \over 2}$$
D
$$ - {5 \over 2}$$
3
WB JEE 2022
MCQ (Single Correct Answer)
+1
-0.25
Change Language

Let P be a point on (2, 0) and Q be a variable point on (y $$-$$ 6)2 = 2(x $$-$$ 4). Then the locus of mid-point of PQ is

A
$${y^2} + x + 6y + 12 = 0$$
B
$${y^2} - x + 6y + 12 = 0$$
C
$${y^2} + x - 6y + 12 = 0$$
D
$${y^2} - x - 6y + 12 = 0$$
4
WB JEE 2022
MCQ (Single Correct Answer)
+1
-0.25
Change Language

AB is a chord of a parabola y2 = 4ax, (a > 0) with vertex A. BC is drawn perpendicular to AB meeting the axis at C. The projection of BC on the axis of the parabola is

A
a unit
B
2a unit
C
8a unit
D
4a unit
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