1
WB JEE 2020
MCQ (Single Correct Answer)
+1
-0.25
Change Language
The domain of $$f(x) = \sqrt {\left( {{1 \over {\sqrt x }} - \sqrt {x + 1} } \right)} $$ is
A
$$x > - 1$$
B
$$( - 1,\infty )\backslash \{ 0\} $$
C
$$\left( {0,{{\sqrt 5 - 1} \over 2}} \right]$$
D
$$\left[ {{{1 - \sqrt 5 } \over 2},0} \right)$$
2
WB JEE 2020
MCQ (Single Correct Answer)
+1
-0.25
Change Language
Let $$y = f(x) = 2{x^2} - 3x + 2$$. The differential of y when x changes from 2 to 1.99 is
A
0.01
B
0.18
C
$$ - $$0.05
D
0.07
3
WB JEE 2020
MCQ (Single Correct Answer)
+1
-0.25
Change Language
If $$\mathop {\lim }\limits_{x \to 0} {\left( {{{1 + cx} \over {1 - cx}}} \right)^{{1 \over x}}} = 4$$, then $$\mathop {\lim }\limits_{x \to 0} {\left( {{{1 + 2cx} \over {1 - 2cx}}} \right)^{{1 \over x}}}$$ is
A
2
B
4
C
16
D
64
4
WB JEE 2020
MCQ (Single Correct Answer)
+1
-0.25
Change Language
Let f : R $$ \to $$ R be twice continuously differentiable (or f" exists and is continuous) such that f(0) = f(1) = f'(0) = 0. Then
A
f"(c) = 0 for some c $$ \in $$ R
B
there is no point for which f"(x) = 0
C
at all points f"(x) > 0
D
at all points f"(x) < 0
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