1
WB JEE 2020
MCQ (More than One Correct Answer)
+2
-0
Change Language
Consider a tangent to the ellipse $${{{x^2}} \over 2} + {{{y^2}} \over 1} = 1$$ at any point. The locus of the mid-point of the portion intercepted between the axes is
A
$${{{x^2}} \over 2} + {{{y^2}} \over 4} = 1$$
B
$${{{x^2}} \over 4} + {{{y^2}} \over 2} = 1$$
C
$${1 \over {3{x^2}}} + {1 \over {4{y^2}}} = 1$$
D
$${1 \over {2{x^2}}} + {1 \over {4{y^2}}} = 1$$
2
WB JEE 2020
MCQ (More than One Correct Answer)
+2
-0
Change Language
Let $$y = {{{x^2}} \over {{{(x + 1)}^2}(x + 2)}}$$. Then $${{{d^2}y} \over {d{x^2}}}$$ is
A
$$2\left[ {{3 \over {{{(x + 1)}^4}}} - {3 \over {{{(x + 1)}^3}}} + {4 \over {{{(x + 2)}^3}}}} \right]$$
B
$$3\left[ {{2 \over {{{(x + 1)}^3}}} + {4 \over {{{(x + 1)}^2}}} - {5 \over {{{(x + 2)}^3}}}} \right]$$
C
$${6 \over {{{(x + 1)}^3}}} - {4 \over {{{(x + 1)}^2}}} + {3 \over {{{(x + 1)}^3}}}$$
D
$${7 \over {{{(x + 1)}^3}}} - {3 \over {{{(x + 1)}^2}}} + {2 \over {{{(x + 1)}^3}}}$$
3
WB JEE 2020
MCQ (More than One Correct Answer)
+2
-0
Change Language
Let $$f(x) = {1 \over 3}x\sin x - (1 - \cos \,x)$$. The smallest positive integer k such that $$\mathop {\lim }\limits_{x \to 0} {{f(x)} \over {{x^k}}} \ne 0$$ is
A
4
B
3
C
2
D
1
4
WB JEE 2020
MCQ (More than One Correct Answer)
+2
-0
Change Language
Tangent is drawn at any point P(x, y) on a curve, which passes through (1, 1). The tangent cuts X-axis and Y-axis at A and B respectively. If AP : BP = 3 : 1, then
A
The differential equation of the curve is $$3x{{dy} \over {dx}} + y = 0$$
B
the differential equation of the curve is $$3x{{dy} \over {dx}} - y = 0$$
C
the curve passes through $$\left( {{1 \over 8},2} \right)$$
D
the normal at (1, 1) is x + 3y = 4
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