Let $f: R \rightarrow R, f(x)=x^3-3 x^2+3 x-2$, then $f^{-1}(x)$ is given by
$1+\sqrt[3]{x+1}$
$1-\sqrt[3]{x+1}$
$\sqrt[3]{x+1}-1$
$\sqrt[3]{x-1}-1$
The least positive non-integral solution of the equation $\sin \pi\left(x^2+x\right)=\sin \pi x^2$ is
Rational
Irrational of form $\sqrt{p}$
Irrational of the form $\frac{\sqrt{p}-1}{4}$, where $p$ is an odd integer
Irrational of the form $\frac{\sqrt{p}+1}{4}$, where $p$ is an even integer
$S=\cot ^{-1}\left(\frac{1+2 \times 6}{4}\right)+\cot ^{-1}\left(\frac{1+3 \times 8}{10}\right)+\cot ^{-1} \left(\frac{1+4 \times 10}{18}\right) \ldots \ldots \ldots$ upto $\infty$ terms is equal to
$\tan ^{-1} 2$
$\cot ^{-1} 2$
$\frac{\pi}{2}-\cot ^{-1} 2$
$-\tan ^{-1} 2$
The area of the region $\left\{(x, y): x y<8,1 \leq y \leq x^2\right\}$ is
$8 \ln 2-\frac{14}{3}$
$16 \ln 2-\frac{14}{3}$
$16 \ln 2-6$
$8 \ln 2-\frac{7}{3}$
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