If the magnetic field in plane electromagnetic wave is
$$ \mathbf{B}=3 \times 10^{-8} \sin \left(1.6 \times 10^3 x+48 \times 10^{10} t\right) \hat{\mathbf{j}} \mathrm{T}, $$
then find the expression of electric field?
$60 \sin \left(1.6 \times 10^3 x+48 \times 10^{10} t\right) \hat{\mathbf{k}} \mathrm{V} / \mathrm{m}$
$3 \times 10^{-8} \sin \left(1.6 \times 10^3 x+48 \times 10^{10} t\right) \hat{\mathrm{i}} \mathrm{V} / \mathrm{m}$
$9 \sin \left(1.6 \times 10^3 x+48 \times 10^{10} t\right) \hat{\mathbf{k}} \mathrm{V} / \mathrm{m}$
$3 \times 10^{-8} \sin \left(1.6 \times 10^3 x+48 \times 10^{10} t\right) \hat{\mathbf{j}} \mathrm{V} / \mathrm{m}$
A laser beam of cross-sectional area $5 \mathrm{~mm}^2$ is 30 mW . Find the magnitude of maximum electric field in this electromagnetic wave.
$2.1 \mathrm{kV} / \mathrm{m}$
$1.4 \mathrm{kV} / \mathrm{m}$
$2 \mathrm{kV} / \mathrm{m}$
$0.5 \mathrm{kV} / \mathrm{m}$
A body of mass $M$ is moving with a uniform speed of $10 \mathrm{~m} / \mathrm{s}$ on frictionless surface under the influence of two forces $F_1$ and $F_2$. The net power of the system is

$10 F_1 F_2 M$
$10\left(F_1+F_2\right) M$
$\left(F_1+F_2\right) M$
zero
An object is projected from surface of Earth with a kinetic energy twice that of escape energy ' $K$ ', from surface of Earth. It's kinetic energy when it reaches far away from Earth is
K
$2 K$
$K / 2$
0
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