Sum to 10 terms of the series $1+2(1 \cdot 1)+3(1 \cdot 1)^2+4(1 \cdot 1)^3+$ $\_\_\_\_$ is
85.12
96.75
92.5
100
The equation of the straight line through the origin and parallel to the line
$$ \begin{aligned} & (b+c) x+(c+a) y+(a+b) z=k= \\ & (b-c) x+(c-a) y+(a-b) z \text { is } \end{aligned} $$
$\frac{x}{b^2-c^2}=\frac{y}{c^2-a^2}=\frac{z}{a^2-b^2}$
$\frac{\boldsymbol{x}}{a^2-b c}=\frac{\boldsymbol{y}}{b^2-c a}=\frac{\boldsymbol{Z}}{c^2-a b}$
$\frac{x}{b}=\frac{y}{c}=\frac{z}{a}$
$\frac{x}{b^2+c^2}=\frac{y}{c^2+a^2}=\frac{z}{a^2+b^2}$
The point $(-2 m, m+1)$ is an interior point of the smaller region bounded by circle $x^2+y^2=4$ and the parabola $y^2=4 x$, then
$-1< m<-5+2 \sqrt{6}$
$-1< m <\frac{3}{5}$
$0 < m < 4$
$-5-2 \sqrt{6}< m< 1$
Total number of 3 letters word that can be formed from the letters of the word 'SAHARANPUR' is equal to
210
247
237
227
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