The focal chord of $y^2=16 x$ is a tangent to $(x-6)^2+y^2=2$, then the possible values of the slope of this chord are
$1,-1$
$-\frac{1}{2}, 2$
$-2, \frac{1}{2}$
$\frac{1}{2}, 2$
14
15
16
None of these
If $\hat{\mathbf{a}} \cdot \hat{\mathbf{b}}=0$, where $\hat{\mathbf{a}}$ and $\hat{\mathbf{b}}$ are unit vectors and the unit vector $\hat{\complement}$ is inclined at an angle $\theta$ to both $\hat{\mathbf{a}}$ and $\hat{\mathbf{b}}$. If $\hat{\mathbf{c}}=m \hat{\mathbf{a}}+n \hat{\mathbf{b}}+p(\hat{\mathbf{a}} \times \hat{\mathbf{b}})$, where, $m, n, p \in R$, then
$-\frac{\pi}{4} \leq \theta \leq \frac{\pi}{4}$
$0 \leq \theta \leq \frac{\pi}{4}$
$\frac{\pi}{4} \leq \theta \leq \frac{3 \pi}{4}$
$0 \leq \theta \leq \frac{3 \pi}{4}$
In the given figure, the equation of the large circle is $x^2+y^2+4 y-5=0$ and the distance between centre is 4 . Then, the equation of smaller circle is

$(x-\sqrt{7})^2+(y-1)^2=1$
$(x+\sqrt{7})^2+(y-1)^2=1$
$x^2+y^2=2 \sqrt{7} x+2 y$
None of the above
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