Arrange the energy of $2 s$ orbitals in increasing order for the atoms $\mathrm{C}, \mathrm{B}, \mathrm{N}$ and O .
$E_{2 s}(\mathrm{O}) < E_{2 s}(\mathrm{~N}) < E_{2 s}(\mathrm{C}) < E_{2 s}(\mathrm{~B})$
$E_{2 s}(\mathrm{~B}) < E_{2 s}(\mathrm{C}) < E_{2 s}(\mathrm{~N}) < E_{2 s}(\mathrm{O})$
$E_{2 s}(\mathrm{~N})< E_{2 s}(\mathrm{O})< E_{2 s}(\mathrm{~B})< E_{2 s}(\mathrm{C})$
$E_{2 s}(\mathrm{C})< E_{2 s}(\mathrm{~B})< E_{2 s}(\mathrm{O})< E_{2 s}(\mathrm{~N})$
Identify the final product $C$ in the following sequence.
$$ \begin{aligned} \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{Br}+(\text { alc. } \mathrm{KOH}) & \xrightarrow{h \nu} A+\mathrm{Br}_2 \longrightarrow B+(\text { alc. } \mathrm{KCN}) \longrightarrow C \end{aligned} $$
$\mathrm{CH}_2=\mathrm{CHCN}$
$\mathrm{CH}_3 \mathrm{CHBrCN}$
$\mathrm{CHBr}=\mathrm{CHCN}$
$\mathrm{CH}_2 \mathrm{BrCH}_2 \mathrm{CN}$
The osmotic pressure of a solution prepared by dissolving 48 mg of $\mathrm{MgCl}_2$ in 500 mL water at $25^{\circ} \mathrm{C}$ is (Assuming complete dissociation).
(Molar mass of $\mathrm{MgCl}_2=95 \mathrm{~g} / \mathrm{mol}, R=0.0821 \mathrm{L} \cdot \mathrm{atm} / \mathrm{mol} \cdot \mathrm{K}$ )
$2.49 \times 10^{-2} \mathrm{~atm}$
$4.98 \times 10^{-2} \mathrm{~atm}$
$2.49 \times 10^{-3} \mathrm{~atm}$
$4.98 \times 10^{-3} \mathrm{~atm}$
Which of the following compounds on reaction with $\mathrm{CH}_3 \mathrm{MgBr}$ followed by acid hydrolysis gives a tertiary alcohol?
$\mathrm{CH}_3 \mathrm{COCH}_3$
$\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CHO}$
$\mathrm{C}_6 \mathrm{H}_5 \mathrm{COOH}$
$\mathrm{C}_6 \mathrm{H}_5 \mathrm{CHO}$
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