1
TS EAMCET 2022 (Online) 20th July Evening Shift
MCQ (Single Correct Answer)
+1
-0

Which of the following is the unit of mobility of a electron in a conductor?

A

$\mathrm{kg}^{-1} \mathrm{~s}^2 \mathrm{~A}^{-1}$

B

$\mathrm{kg}^{-1} \mathrm{~s}^2 \mathrm{~A}$

C

$\mathrm{kg}^{-1} \mathrm{~ms}^2 \mathrm{~A}^{-1}$

D

$\mathrm{kg}-\mathrm{ms}^{-1} \mathrm{~A}^{-1}$

2
TS EAMCET 2022 (Online) 20th July Evening Shift
MCQ (Single Correct Answer)
+1
-0

A car starts at time $t=0$ from an initial speed of $10 \mathrm{~m} / \mathrm{s}$ and accelerates uniformly with $2 \mathrm{~m} / \mathrm{s}^2$ on a straight road for time $0 \leq t \leq 10 \mathrm{~s}$. Let $s_1$ and $s_2$ be the distance covered by the car in time $3 \leq t \leq 4 \mathrm{~s}$ and $4 \leq t \leq 5 \mathrm{~s}$, respectively. The ratio $\frac{s_2}{s_1}$ is

A

1

B

$\frac{19}{7}$

C

$\frac{9}{7}$

D

$\frac{5}{3}$

3
TS EAMCET 2022 (Online) 20th July Evening Shift
MCQ (Single Correct Answer)
+1
-0

Particle $A$ (which was located at the origin at time $t=0$ ) is moving along the $X$-axis with a constant speed of $1 \mathrm{~m} / \mathrm{s}$. Location of particle $B$ which is moving along the $Y$-axis is given by $y=c t^2$, where $c=1 \mathrm{~m} / \mathrm{s}^2$. Find the speed of particle $A$ relative to particle $B$ at $t=1 \mathrm{~s}$

A

$\sqrt{5} \mathrm{~m} / \mathrm{s}$

B

$2 \mathrm{~m} / \mathrm{s}$

C

$1 \mathrm{~m} / \mathrm{s}$

D

$0 \mathrm{~m} / \mathrm{s}$

4
TS EAMCET 2022 (Online) 20th July Evening Shift
MCQ (Single Correct Answer)
+1
-0

A particle is moving in $X Y$-plane as $\mathbf{x}=\left(4 t+t^2\right) \hat{\mathbf{i}}$, $\mathbf{y}=\left(2 t+\frac{t^2}{2}\right) \hat{\mathbf{j}}$, where $\mathbf{x}$ and $\mathbf{y}$ are displacements measured along $X$ and $Y$-axes respectively, in metres and $t$ in seconds, What is the velocity of the particle?

A

$\mathbf{v}=(4+t) \hat{\mathbf{i}}+(2+t) \hat{\mathbf{j}} \mathrm{m} / \mathrm{s}$

B

$\mathbf{v}=(4+2 t) \hat{\mathbf{i}}+(2+t) \hat{\mathbf{j}} \mathrm{m} / \mathrm{s}$

C

$\mathbf{v}=(4+2 t) \hat{\mathbf{i}}+\left(2+\frac{t}{2}\right) \hat{\mathbf{j}} \mathrm{m} / \mathrm{s}$

D

$\mathbf{v}=(4+t) \hat{\mathbf{i}}+\left(2+\frac{t}{2}\right) \hat{\mathbf{j}} \mathrm{m} / \mathrm{s}$

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