1
TS EAMCET 2022 (Online) 20th July Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $m$ is the length of the latusrectum and $n$ is the length of the major-axis of the ellipse $25 x^2+16 y^2-150 x-64 y-111=0$, then the ordered pair $(m, n)=$

A

$\left(\frac{16}{5}, 10\right)$

B

$\left(\frac{32}{5}, 10\right)$

C

$\left(\frac{25}{2}, 8\right)$

D

$\left(\frac{25}{4}, 8\right)$

2
TS EAMCET 2022 (Online) 20th July Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $P(\theta)$ and $Q\left(\frac{\pi}{2}+\theta\right)$ are two points on the ellipse $\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$ and the locus of mid-point of $P Q$ is $\frac{x^2}{\alpha^2}+\frac{y^2}{\beta^2}=1$, then $\frac{a+b}{\alpha+\beta}=$

A

$\frac{1}{\sqrt{2}}$

B

$\sqrt{3}$

C

$\frac{1}{\sqrt{3}}$

D

$\sqrt{2}$

3
TS EAMCET 2022 (Online) 20th July Evening Shift
MCQ (Single Correct Answer)
+1
-0

Let $S$ be the focus of the hyperbola $x^2-2 y^2=1$ lying on the positive $X$-axis. Let $P(-1,1)$ be a given point. Then, the area of the triangle formed by the line $P S$ with the coordinate axes is (in sq. units)

A

$\frac{\sqrt{2}}{2(\sqrt{2}+3)}$

B

$\frac{\sqrt{6}}{2(2+\sqrt{6})}$

C

$\frac{3}{2(2+\sqrt{6})}$

D

$\frac{\sqrt{3}}{2(\sqrt{2}+\sqrt{3})}$

4
TS EAMCET 2022 (Online) 20th July Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $P\left(\frac{\pi}{6}\right)$ is a point on the hyperbola $\frac{x^2}{a^2}-\frac{y^2}{b^2}=1, S, S$ are its foci and $S P+S P=2 | S P-S P$|, then $e=$

A

$\sqrt{2}$

B

2

C

$\sqrt{3}$

D

3

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