1
TS EAMCET 2020 (Online) 14th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

If in a Young's double slit experiment the slit separation is doubled and the distance of the screen from the slits is reduced to half, then the fringe widths become how many times their original value?

A

$\frac{1}{2}$

B

2

C

$\frac{1}{4}$

D

4

2
TS EAMCET 2020 (Online) 14th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

In a uniformly charged sphere of total charge $Q$ and radius $R$, the electric field $E$ is plotted as function of distance from the centre of the sphere. The graph which would correspond to the above description will be

A

TS EAMCET 2020 (Online) 14th September Evening Shift Physics - Electrostatics Question 1 English Option 1

B

TS EAMCET 2020 (Online) 14th September Evening Shift Physics - Electrostatics Question 1 English Option 2

C

TS EAMCET 2020 (Online) 14th September Evening Shift Physics - Electrostatics Question 1 English Option 3

D

TS EAMCET 2020 (Online) 14th September Evening Shift Physics - Electrostatics Question 1 English Option 4

3
TS EAMCET 2020 (Online) 14th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

Electric charges $+q$ and $-q$ are placed at points $A$ and $B$ respectively which are at a distance of $2 L$ apart. If $C$ is the midpoint between $A$ and $B$, then the work done in moving a charge $+Q$ along the semi-circle $C R D$ is

TS EAMCET 2020 (Online) 14th September Evening Shift Physics - Electrostatics Question 2 English

A

$\frac{q Q}{2 \pi \varepsilon_0 L}$

B

$\frac{q Q}{6 \pi \varepsilon_0 L}$

C

$-\frac{q Q}{6 \pi \varepsilon_0 L}$

D

$\frac{q Q}{4 \pi \varepsilon_0 L}$

4
TS EAMCET 2020 (Online) 14th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

Find the equivalent resistance between point $A$ and $B$ in the following circuit. (The resistance of each resistor is $R$ )

TS EAMCET 2020 (Online) 14th September Evening Shift Physics - Current Electricity Question 1 English

A

$\frac{34}{55} R$

B

$\frac{45}{77} R$

C

$\frac{3}{5} R$

D

$\frac{5}{3} R$

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