TS EAMCET 2020 (Online) 14th September Evening Shift | TS EAMCET Year Wise Previous Years Questions

TS EAMCET 2020 (Online) 14th September Evening Shift

MCQ (Single Correct Answer)

-0

$$ \text { Match the items of List-I to the items of List-II } $$

$$ \text { List-I } $$		$$ \text { List-II } $$
A.	The period of $\sin ^2 x$ is	I.	$$ \frac{2 \pi}{3} $$
B.	$$ \begin{aligned} &\text { Maximum value of }\\ &\frac{\pi}{3}(\sqrt{3} \cos 3 x+\sin 3 x) \end{aligned} $$	II.	$$ 12 \pi $$
C.	The period of $\sin \frac{x}{3}+\cos \frac{x}{2}$ is	III.	$$ \frac{\pi}{2} $$
D.	Intersection points of $y=\|\sin x\|$ and $y=1$ in $(0, \pi)$	IV.	$$ \frac{3\pi}{2} $$
		V	$$ \pi $$

$$ \text { The correct match is } $$

A	B	C	D
V	I	II	III

A	B	C	D
IV	I	II	III

A	B	C	D
III	I	IV	V

A	B	C	D
IV	III	II	V

TS EAMCET 2020 (Online) 14th September Evening Shift

MCQ (Single Correct Answer)

-0

If $\cot \left(\frac{A}{2}\right)=\sqrt{\frac{1+a}{1-a}} \cdot \cot \left(\frac{\theta}{2}\right)$, then $\cos \theta=$

$\frac{(\cos A)+a}{1-a \cos A}$

$\frac{(\cos A)-a}{1-a \cos A}$

$\frac{(\cos A)-a}{1+a \cos A}$

$\frac{(\cos A)+a}{1+a \cos A}$

TS EAMCET 2020 (Online) 14th September Evening Shift

MCQ (Single Correct Answer)

-0

If $\sum\limits_{n=1}^k \tan ^{-1}\left(\frac{1}{n^2+3 n+3}\right)=\tan ^{-1} \alpha$, then $\alpha=$

$\frac{k}{k+2}$

$\frac{2 k}{2 k+1}$

$\frac{k}{2 k+5}$

$\frac{3 k}{4 k+5}$

TS EAMCET 2020 (Online) 14th September Evening Shift

MCQ (Single Correct Answer)

-0

The set of values of $x$ such that $\tan ^{-1}\left(\frac{x}{x-2}\right)-\tan ^{-1}\left(\frac{x}{2 x-1}\right)=\tan ^{-1}\left(\frac{2}{3}\right)$ is

$\phi$

$\left\{\frac{1}{2}\right\}$

$\left\{\frac{1}{3}, 2\right\}$

$\left\{\frac{1}{3}, 4\right\}$

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