1
TS EAMCET 2020 (Online) 11th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

In a triangle $A B C$, if $c=9, s=10$ and $\Delta=10 \sqrt{2}$ then $b\left[1+\sqrt{2} \tan \left(\frac{A-B}{2}\right)\right]=$

A

$a\left[1-\sqrt{2} \tan \left(\frac{A-B}{2}\right)\right]$

B

$C\left[1-\sqrt{2} \tan \left(\frac{A-B}{2}\right)\right]$

C

$a\left[\sqrt{2} \tan \left(\frac{A-B}{2}\right)-1\right]$

D

$C\left[\sqrt{2} \tan \left(\frac{A-B}{2}\right)-1\right]$

2
TS EAMCET 2020 (Online) 11th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

In a $\triangle A B C, \cot A+\cot B+\cot C=$

A

$\frac{a^2+b^2+c^2}{\Delta}$

B

$\frac{a+b+c}{4 \Delta}$

C

$\frac{a^2+b^2+c^2}{4 \Delta}$

D

$\frac{a^2+b^2+c^2}{2 \Delta}$

3
TS EAMCET 2020 (Online) 11th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $A(4,7,8), B(2,3,4)$ and $C(2,5,7)$ are the vertices of $\triangle A B C$, then the length of the internal bisector of the angle $A$ is

A

$\frac{1}{2} \sqrt{34}$

B

$\frac{1}{3} \sqrt{34}$

C

$\frac{2}{3} \sqrt{34}$

D

$\frac{3}{8} \sqrt{17}$

4
TS EAMCET 2020 (Online) 11th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

For scalars $\lambda, \mu$ if the vector equation of a plane is $\mathbf{r}=(2+3 \lambda-\mu) \hat{\mathbf{i}}+(1-2 \lambda+3 \mu) \hat{\mathbf{j}}+(-2+2 \lambda+\mu) \hat{\mathbf{k}}$, then its Cartesian equation is

A

$8 x-5 y-7 z+35=0$

B

$8 x-5 y+7 z-35=0$

C

$8 x+5 y-7 z+35=0$

D

$8 x+5 y-7 z-35=0$

TS EAMCET Papers

All year-wise previous year question papers