1
TS EAMCET 2020 (Online) 11th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $x=\left(\tan ^{-1} \frac{1}{5}+\tan ^{-1} \frac{1}{8}\right)$, then $\frac{\sin x+\cos x}{\tan x}=$

A

$\frac{12}{\sqrt{10}}$

B

$\frac{15}{\sqrt{10}}$

C

$\frac{1}{\sqrt{10}}$

D

$\frac{6 \sqrt{2}}{\sqrt{10}}$

2
TS EAMCET 2020 (Online) 11th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

If for $|x|>1, \tanh ^{-1}\left(\frac{1}{x}\right)+\operatorname{coth}^{-1}(x)=\log _e(f(x))$, then $f(-5)=$

A

$\frac{3}{2}$

B

$\frac{-2}{3}$

C

$\frac{2}{3}$

D

$\frac{1}{3}$

3
TS EAMCET 2020 (Online) 11th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

In a triangle $A B C$, if $a

A

3

B

4

C

2

D

6

4
TS EAMCET 2020 (Online) 11th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

In a triangle $A B C$, if $c=9, s=10$ and $\Delta=10 \sqrt{2}$ then $b\left[1+\sqrt{2} \tan \left(\frac{A-B}{2}\right)\right]=$

A

$a\left[1-\sqrt{2} \tan \left(\frac{A-B}{2}\right)\right]$

B

$C\left[1-\sqrt{2} \tan \left(\frac{A-B}{2}\right)\right]$

C

$a\left[\sqrt{2} \tan \left(\frac{A-B}{2}\right)-1\right]$

D

$C\left[\sqrt{2} \tan \left(\frac{A-B}{2}\right)-1\right]$

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