1
TG EAPCET 2025 (Online) 2nd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If all the letters of the word MOST are permuted and the words (with or without meaning) thus obtained are arranged in the dictionary order, then the rank of the words STOM when counted from the rank of the word MOST, is

A

24

B

21

C

12

D

18

2
TG EAPCET 2025 (Online) 2nd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The constant term in the expansion of $\left(1+\frac{1}{x}\right)^{20}\left(30 x(1+x)^{29}+(1+x)^{30}\right)$ is

A

${ }^{50} \mathrm{C}_{20}+30 \cdot{ }^{50} \mathrm{C}_{29}$

B

${ }^{50} \mathrm{C}_{19}+30 \cdot{ }^{49} \mathrm{C}_{19}$

C

${ }^{50} \mathrm{C}_{20}+30 \cdot{ }^{49} \mathrm{C}_{20}$

D

${ }^{50} \mathrm{C}_{20}+30 \cdot{ }^{49} \mathrm{C}_{19}$

3
TG EAPCET 2025 (Online) 2nd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

When $|x|>3$, then coefficient of $\frac{1}{x^n}$ in the expansion of $x^{3 / 2}(3+x)^{1 / 2}$ is

A

$(-1)^n \frac{1 \cdot 3 \cdot 5 \ldots(2 n-1)}{2^n n!} 3^n$

B

$(-1)^{n+1} \frac{1 \cdot 3 \cdot 5 \ldots(2 n+1)}{2^{n+2}(n+2)!} 3^{n+2}$

C

$(-1)^{n+1} \frac{1 \cdot 3 \cdot 5 \ldots(2 n-1)}{2^n n!} 3^{n+1}$

D

$(-1)^{n+1} \frac{1 \cdot 3 \cdot 5 \ldots(2 n+1)}{2^{n+3}(n+2)!} 3^{n+1}$

4
TG EAPCET 2025 (Online) 2nd May Evening Shift
MCQ (Single Correct Answer)
+1
-0

If $\frac{x^2-3}{(x+2)\left(x^2+1\right)}=\frac{A}{x+2}+\frac{B x+C}{\left(x^2+1\right)}$, then $3 A+2 B-C=$

A

$\frac{8}{5}$

B

$\frac{16}{5}$

C

$\frac{3}{5}$

D

$\frac{19}{5}$

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